Given a triangle of consecutive odd numbers: 1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 ... find the triangle's row knowing its index (the rows are 1-indexed), e.g.: odd_row(1) == [1] odd_row(2) == [3, 5] odd_row(3) == [7, 9, 11] Note: your code should be optimized to handle big inputs. Solution #include std::vector odd_row(unsigned long long n) { std::vector vResult; unsigned long long c = n * (n-..
